Optimal. Leaf size=87 \[ -\frac {1}{6 x^3}+\frac {1}{4 b^2 x}-\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{4 b^3}+\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{2 b x^2}-\frac {\sin ^2\left (a+\frac {b}{x}\right )}{2 b^2 x} \]
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Rubi [A]
time = 0.04, antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {3460, 3392, 30,
2715, 8} \begin {gather*} -\frac {\sin \left (a+\frac {b}{x}\right ) \cos \left (a+\frac {b}{x}\right )}{4 b^3}-\frac {\sin ^2\left (a+\frac {b}{x}\right )}{2 b^2 x}+\frac {\sin \left (a+\frac {b}{x}\right ) \cos \left (a+\frac {b}{x}\right )}{2 b x^2}+\frac {1}{4 b^2 x}-\frac {1}{6 x^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 30
Rule 2715
Rule 3392
Rule 3460
Rubi steps
\begin {align*} \int \frac {\sin ^2\left (a+\frac {b}{x}\right )}{x^4} \, dx &=-\text {Subst}\left (\int x^2 \sin ^2(a+b x) \, dx,x,\frac {1}{x}\right )\\ &=\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{2 b x^2}-\frac {\sin ^2\left (a+\frac {b}{x}\right )}{2 b^2 x}-\frac {1}{2} \text {Subst}\left (\int x^2 \, dx,x,\frac {1}{x}\right )+\frac {\text {Subst}\left (\int \sin ^2(a+b x) \, dx,x,\frac {1}{x}\right )}{2 b^2}\\ &=-\frac {1}{6 x^3}-\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{4 b^3}+\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{2 b x^2}-\frac {\sin ^2\left (a+\frac {b}{x}\right )}{2 b^2 x}+\frac {\text {Subst}\left (\int 1 \, dx,x,\frac {1}{x}\right )}{4 b^2}\\ &=-\frac {1}{6 x^3}+\frac {1}{4 b^2 x}-\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{4 b^3}+\frac {\cos \left (a+\frac {b}{x}\right ) \sin \left (a+\frac {b}{x}\right )}{2 b x^2}-\frac {\sin ^2\left (a+\frac {b}{x}\right )}{2 b^2 x}\\ \end {align*}
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Mathematica [A]
time = 0.09, size = 54, normalized size = 0.62 \begin {gather*} \frac {-4 b^3+6 b x^2 \cos \left (2 \left (a+\frac {b}{x}\right )\right )-3 \left (-2 b^2 x+x^3\right ) \sin \left (2 \left (a+\frac {b}{x}\right )\right )}{24 b^3 x^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(196\) vs.
\(2(77)=154\).
time = 0.06, size = 197, normalized size = 2.26
method | result | size |
risch | \(-\frac {1}{6 x^{3}}+\frac {\cos \left (\frac {2 a x +2 b}{x}\right )}{4 b^{2} x}+\frac {\left (2 b^{2}-x^{2}\right ) \sin \left (\frac {2 a x +2 b}{x}\right )}{8 b^{3} x^{2}}\) | \(56\) |
norman | \(\frac {-\frac {1}{6}+\frac {x \tan \left (\frac {a}{2}+\frac {b}{2 x}\right )}{b}-\frac {\left (\tan ^{2}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{3}-\frac {\left (\tan ^{4}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{6}+\frac {x^{2}}{4 b^{2}}-\frac {x^{3} \tan \left (\frac {a}{2}+\frac {b}{2 x}\right )}{2 b^{3}}+\frac {x^{3} \left (\tan ^{3}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{2 b^{3}}-\frac {3 x^{2} \left (\tan ^{2}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{2 b^{2}}+\frac {x^{2} \left (\tan ^{4}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{4 b^{2}}-\frac {x \left (\tan ^{3}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )}{b}}{\left (1+\tan ^{2}\left (\frac {a}{2}+\frac {b}{2 x}\right )\right )^{2} x^{3}}\) | \(179\) |
derivativedivides | \(-\frac {a^{2} \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-2 a \left (\left (a +\frac {b}{x}\right ) \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-\frac {\left (a +\frac {b}{x}\right )^{2}}{4}+\frac {\left (\sin ^{2}\left (a +\frac {b}{x}\right )\right )}{4}\right )+\left (a +\frac {b}{x}\right )^{2} \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-\frac {\left (a +\frac {b}{x}\right ) \left (\cos ^{2}\left (a +\frac {b}{x}\right )\right )}{2}+\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{4}+\frac {b}{4 x}+\frac {a}{4}-\frac {\left (a +\frac {b}{x}\right )^{3}}{3}}{b^{3}}\) | \(197\) |
default | \(-\frac {a^{2} \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-2 a \left (\left (a +\frac {b}{x}\right ) \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-\frac {\left (a +\frac {b}{x}\right )^{2}}{4}+\frac {\left (\sin ^{2}\left (a +\frac {b}{x}\right )\right )}{4}\right )+\left (a +\frac {b}{x}\right )^{2} \left (-\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{2}+\frac {a}{2}+\frac {b}{2 x}\right )-\frac {\left (a +\frac {b}{x}\right ) \left (\cos ^{2}\left (a +\frac {b}{x}\right )\right )}{2}+\frac {\cos \left (a +\frac {b}{x}\right ) \sin \left (a +\frac {b}{x}\right )}{4}+\frac {b}{4 x}+\frac {a}{4}-\frac {\left (a +\frac {b}{x}\right )^{3}}{3}}{b^{3}}\) | \(197\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.40, size = 69, normalized size = 0.79 \begin {gather*} \frac {3 \, {\left ({\left (-i \, \Gamma \left (3, \frac {2 i \, b}{x}\right ) + i \, \Gamma \left (3, -\frac {2 i \, b}{x}\right )\right )} \cos \left (2 \, a\right ) - {\left (\Gamma \left (3, \frac {2 i \, b}{x}\right ) + \Gamma \left (3, -\frac {2 i \, b}{x}\right )\right )} \sin \left (2 \, a\right )\right )} x^{3} - 16 \, b^{3}}{96 \, b^{3} x^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.37, size = 72, normalized size = 0.83 \begin {gather*} \frac {6 \, b x^{2} \cos \left (\frac {a x + b}{x}\right )^{2} - 2 \, b^{3} - 3 \, b x^{2} + 3 \, {\left (2 \, b^{2} x - x^{3}\right )} \cos \left (\frac {a x + b}{x}\right ) \sin \left (\frac {a x + b}{x}\right )}{12 \, b^{3} x^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 654 vs.
\(2 (68) = 136\).
time = 2.25, size = 654, normalized size = 7.52 \begin {gather*} \begin {cases} - \frac {2 b^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} - \frac {4 b^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} - \frac {2 b^{3}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} - \frac {12 b^{2} x \tan ^{3}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} + \frac {12 b^{2} x \tan {\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} + \frac {3 b x^{2} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} - \frac {18 b x^{2} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} + \frac {3 b x^{2}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} + \frac {6 x^{3} \tan ^{3}{\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} - \frac {6 x^{3} \tan {\left (\frac {a}{2} + \frac {b}{2 x} \right )}}{12 b^{3} x^{3} \tan ^{4}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 24 b^{3} x^{3} \tan ^{2}{\left (\frac {a}{2} + \frac {b}{2 x} \right )} + 12 b^{3} x^{3}} & \text {for}\: b \neq 0 \\- \frac {\sin ^{2}{\left (a \right )}}{3 x^{3}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 3.55, size = 153, normalized size = 1.76 \begin {gather*} \frac {6 \, a^{2} \sin \left (\frac {2 \, {\left (a x + b\right )}}{x}\right ) - \frac {12 \, {\left (a x + b\right )} a^{2}}{x} - 6 \, a \cos \left (\frac {2 \, {\left (a x + b\right )}}{x}\right ) - \frac {12 \, {\left (a x + b\right )} a \sin \left (\frac {2 \, {\left (a x + b\right )}}{x}\right )}{x} + \frac {12 \, {\left (a x + b\right )}^{2} a}{x^{2}} + \frac {6 \, {\left (a x + b\right )} \cos \left (\frac {2 \, {\left (a x + b\right )}}{x}\right )}{x} + \frac {6 \, {\left (a x + b\right )}^{2} \sin \left (\frac {2 \, {\left (a x + b\right )}}{x}\right )}{x^{2}} - \frac {4 \, {\left (a x + b\right )}^{3}}{x^{3}} - 3 \, \sin \left (\frac {2 \, {\left (a x + b\right )}}{x}\right )}{24 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.70, size = 64, normalized size = 0.74 \begin {gather*} \frac {\frac {b\,x^2\,\cos \left (2\,a+\frac {2\,b}{x}\right )}{4}-\frac {b^3}{6}+\frac {b^2\,x\,\sin \left (2\,a+\frac {2\,b}{x}\right )}{4}}{b^3\,x^3}-\frac {\sin \left (2\,a+\frac {2\,b}{x}\right )}{8\,b^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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